Figure 1 |
The sum of the digits of a number is another example of a number property that is not intrinsic. In the case of 25652, the digit sum is 20. However, in base 8 the number is 62064 and the digit sum is \(22_8\), which is 18 in base 10. Contrast this with the sum of the prime factors of 25652 in bases 10 and 8 (ignoring multiplicity). In base 10, the sum is 66. In base 8, the factors are \(2_8\), \(13_8\) and \(65_8\) and so the sum is \(102_8\) or 66 in base 10. So having clarified the difference between intrinsic and base-dependent number properties, what are some of the most important properties of the former type of numbers?
I'll continue using 25652 as an example. To begin the divisors, and particularly the prime divisors, are all important. For 25652, as already noted, the divisors are:$$1, 2, 4, 11, 22, 44, 53, 106, 121, 212, 242, 484, 583, 1166, 2332, 6413, 12826, 25652$$The prime divisors are \( 2, 2, 11, 11, 53 \) and these uniquely define the number. 25652 has an interesting property that does not relate to its own divisors but instead relates to the proper divisors of other numbers. 25652 is an untouchable number, because it is not equal to the sum of proper divisors of any number. The proper divisors of 25652 are 1, 2, 4, 11, 22, 44, 53, 106, 121, 212, 242, 484, 583, 1166, 2332, 6413, 12826 and these add to 25137. This means that 25137 is not an untouchable number because it can be formed from the addition of the proper divisors of 25652. This talk of adding up divisors leads us on to the sigma function.
The sigma function can be used to find the number of divisors, the sum of these divisors, the sum of the squares of these divisors, the sum of the cubes of these divisors and so on. So-called sigma zero, written as \( \sigma_0\), returns the number of divisors or the sum of the divisors raised to the zero power. \( \sigma_1\) returns the sum of the divisors raised to the first power and so on. This is the result:
\( \sigma_1(25652)=50274\)
\( \sigma_2(25652)=871164630\)
\( \sigma_3(25652)=19267967775942\)
Also of interest is the count of numbers that are relatively prime to 25652 where 1 is regarded as being relatively prime to all numbers. This is known as the totient of the number and can be written as \( \phi=11440 \). All multiples of 2, 11 and 53 (and 25652 itself) will be excluded from this count. For prime numbers, the totient will always be one less than the number itself. For example, 25667 is prime and its totient is 25666.
Moving along, we note that some numbers are so-called square numbers. An example of such a number is 25600 which is equal to the square of 160. Visually, this number could be represented as shown in Figure 2.
In the case of 25652, it is not a square number but it can be represented a sum of two squares, since$$25652=23716 + 1936 = 154^2 + 44^2 $$So, visually, the number could be represented as shown in Figure 3:
Only certain numbers can be represented as a sum of two squares. If a number has a 4k+3 prime factor that is raised to an odd number (1, 3, 5, .. ), then it cannot be represented as a sum of two squares. Most numbers can be represented as sum of three squares, provided that there is not a remainder of 7 when the number is divided by 8. 25652 gives a remainder of 4 when divided by 8 and it can be represented as a sum of three squares in 20 different ways as shown in Figure 4:
Visually, the nineteen triplets in Figure 4 that contain no zeroes, could be used as the sides of three squares, to represent 25652. The same approach can be used for cubes. For example:$$25665=11^3+23^3+23^3$$Rather less frequently, a number can be represented as a sum of two cubes. For example:$$25720 = 11^3 + 29^3 $$Such numbers can be envisaged as comprising three cubes (in the case of 25665) or two cubes (in the case of 25720). See Figure 5 for a not-to-scale representation of 25720.
In my previous post, I considered the seed numbers that would be needed to make a number a part of a Fibonacci sequence. In the case of 25652, these numbers would be 52 and 146, producing the sequence:$$25652,15854,9798,6056,3742,2314,1428,886,542,344,198,146,52$$Similarly, the three seed numbers for 25652 to be part of a tribonacci sequence are 10, 30 and 63, producing the sequence:$$25652,13947,7583,4122,2242,1219,661,362,196,103,63,30,10$$So I could go on but I'll leave off there and try to summarise things via Figure 6.
Moving along, we note that some numbers are so-called square numbers. An example of such a number is 25600 which is equal to the square of 160. Visually, this number could be represented as shown in Figure 2.
Figure 2 |
In the case of 25652, it is not a square number but it can be represented a sum of two squares, since$$25652=23716 + 1936 = 154^2 + 44^2 $$So, visually, the number could be represented as shown in Figure 3:
Figure 3 |
Only certain numbers can be represented as a sum of two squares. If a number has a 4k+3 prime factor that is raised to an odd number (1, 3, 5, .. ), then it cannot be represented as a sum of two squares. Most numbers can be represented as sum of three squares, provided that there is not a remainder of 7 when the number is divided by 8. 25652 gives a remainder of 4 when divided by 8 and it can be represented as a sum of three squares in 20 different ways as shown in Figure 4:
Figure 4 |
Figure 5 |
Visually, the nineteen triplets in Figure 4 that contain no zeroes, could be used as the sides of three squares, to represent 25652. The same approach can be used for cubes. For example:$$25665=11^3+23^3+23^3$$Rather less frequently, a number can be represented as a sum of two cubes. For example:$$25720 = 11^3 + 29^3 $$Such numbers can be envisaged as comprising three cubes (in the case of 25665) or two cubes (in the case of 25720). See Figure 5 for a not-to-scale representation of 25720.
In my previous post, I considered the seed numbers that would be needed to make a number a part of a Fibonacci sequence. In the case of 25652, these numbers would be 52 and 146, producing the sequence:$$25652,15854,9798,6056,3742,2314,1428,886,542,344,198,146,52$$Similarly, the three seed numbers for 25652 to be part of a tribonacci sequence are 10, 30 and 63, producing the sequence:$$25652,13947,7583,4122,2242,1219,661,362,196,103,63,30,10$$So I could go on but I'll leave off there and try to summarise things via Figure 6.
Figure 6 |
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