Edge With Decimal Rounded 1 20.645729 21 2 82.582915 83 3 185.81156 186 4 330.33166 330 5 516.14322 516 6 743.24624 743 7 1011.6407 1012 8 1321.3266 1321 9 1672.3040 1672 10 2064.5729 2065 11 2498.1332 2498 12 2972.9849 2973 13 3489.1282 3489 14 4046.5628 4047 15 4645.2890 4645 16 5285.3066 5285 17 5966.6156 5967 18 6689.2161 6689 19 7453.1081 7453 20 8258.2915 8258 21 9104.7664 9105 22 9992.5327 9993 23 10921.591 10922 24 11891.940 11892 25 12903.581 12904 26 13956.513 13957 27 15050.736 15051 28 16186.251 16186 29 17363.058 17363 30 18581.156 18581 31 19840.545 19841 32 21141.226 21141 33 22483.199 22483 34 23866.462 23866 35 25291.018 25291 36 26756.865 26757 37 28264.003 28264 38 29812.432 29812 39 31402.154 31402 40 33033.166 33033 41 34705.470 34705 42 36419.066 36419 43 38173.953 38174 44 39970.131 39970
Friday, 21 August 2026
Surface Area of a Regular Dodecadhedron
Wednesday, 19 August 2026
Super Sphenic Numbers
The number associated with my diurnal age today (28262) is what might be termed a "super sphenic number" as I'll explain in this post. Firstly however, its factorisation:$$28262=2 \times 13 \times 1087$$If we reverse its digits, we get the number 26282 and this number is also sphenic:$$26282 = 2 \times 17 \times 773$$Let's now concatenate the factors of 28262 in ascending order. This gives us the number 2131087 which is also sphenic:$$2131087 = 7 \times 167 \times 1823$$28262 has a sum of digits of 20 and if we add this to the original number we get the palindromic number 28282 which is also sphenic:$$28262+20=28282 = 2 \times 79 \times 179$$The number has a product of digits of 384 and if we subtract this from the original number we get 27878 which is sphenic:$$28262 - 384 = 27878 = 2 \times 53 \times 263$$If we consider only the internal digits of 28262, we get the number 826 which is also sphenic:$$2\, 826 \, 2 \rightarrow826=2 \times 7 \times 59$$When a sphenic number is considered as a sphenic brick then it has an associated number in the form of the brick's surface area. In the case of 28262, this associated surface area is 32662 square units and this number too is sphenic:$$32662 = 2 \times 7 \times 2333$$28262 has a sum of proper divisors that is also sphenic:$$ \sigma(28262) - 28262 =17434 = 2 \times 23 \times 379 $$The number has a sum of prime factors (1102) that is sphenic:$$2 +13+1087=1102 = 2 \times 19 \times 29$$28262 has a totient of 13032 which is not sphenic but its cototient (number - totient) of 15230 is:$$28262 - 13032 = 15230 = 2 \times 5 \times 1523$$So we can see that 28262 may well be termed a super sphenic number because of the above associations.
Friday, 30 August 2024
Dancing Digits
Whenever I'm confronted with a number associated with my diurnal age that seems to have no interesting properties, I inevitably find something very special and interesting about that number. Yesterday's number, 27542, was a number of this sort and it took me a day to stumble upon what's interesting about it.
My starting point was that it's a sphenic number because:$$2542=2 \times 47 \times 293$$Such numbers can be viewed as sphenic bricks with the three prime factors corresponding to the length, width and height. The surface area of such a brick means that there is always a second number that is inextricably linked to the original sphenic number and I've written about this in earlier posts. In the case of 27542, this second number and the surface area of the brick is 28902. This second number however, is also sphenic since we have:$$28902=2 \times 3 \times 4817$$This means that we can find the surface area of this second brick. It is 48182 which is not sphenic. However, we now have a triplet of numbers formed:$$27542, 28902, 48182$$If we find the product of these three numbers, it turns out to be an interesting number:$$27542 \times 28902 \times 48182 = 38353781868888$$It's interesting because it's 14 digits long and the digit 8 comprises precisely half of them.
The question then is how common is it for such triplets of numbers, when multiplied, to generate a number in which a single digit comprises at least 50% of all the digits? Let's reflect on the criteria for such numbers:
- the number must be sphenic and constitutes the first sphenic brick: p
- the surface area of this brick must also be a sphenic number: q
- this second number constitutes the second sphenic brick
- the surface area of this second brick constitutes the third number: r
- the product of p, q and r must contain a digit that comprises at least 50% of the digits of the number.
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Figure 1: plethora of the digit 8 |
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Figure 4: plethora of the digit 4 |
For digit 6, 7 and 9 only one result is found in each case. See Figures 5, 6, 7 and 8.
Sunday, 5 March 2023
The Horn Torus
Tuesday, 8 November 2022
Reversible Sphenic Numbers
There is the reversible prime, known as an emirp. There is the reversible semiprime, known as an emirpimes, and then there is the reversible sphenic number, known as an cinehps. This is a rather ugly term so I'll just use the term reversible sphenic number. An example of an emirp is 17 whose reversal, 71, is also prime. An example of an emirpimes is 26 = 2 x 13 whose reversal, 62 = 2 x 31, is also a semiprime. The first example of a cinehps is 165 = 3 x 5 x 11 whose reversal, 561 = 3 x 11 x 17, is also a sphenic number.
These numbers form OEIS A270175:
A270175 | Cinehps numbers: sphenic numbers whose reversal is a different sphenic number. |
Note that palindromic sphenic numbers are excluded. The initial members of the sequence are:
165, 246, 285, 286, 366, 418, 435, 438, 498, 534, 561, 582, 609, 642, 663, 682, 759, 814, 834, 894, 906, 957, 1002, 1023, 1034, 1066, 1095, 1113, 1131, 1185, 1209, 1239, 1245, 1265, 1311, 1342, 1353, 1374, 1398, 1419, 1443, 1446, 1479, 1515, 1526, 1542, 1545, ...
Up to the one million mark, these numbers total 5.28% of the range. One of the concepts associated with a sphenic number is that of the sphenic brick. Let's consider a sphenic number \(n\) whose factors are \(a,b,c\). The sphenic brick is the three dimensional cuboid with volume of \(n\) cubic units and linear dimensions of \(a,b\) and \(c\) units.
366 = 2 x 3 x 61 --> 622 and 663 = 3 x 13 x 17 --> 6223245 = 5 x 11 x 59 --> 1998 and 5423 = 11 x 17 x 29 --> 19983685 = 5 x 11 x 67 --> 2254 and 5863 = 11 x 13 x 41 --> 2254921239 = 11 x 89 x 941 --> 190158 and 932129 = 11 x 101 x 839 --> 190158
None of the sphenic bricks associated with these numbers look like bricks because they are all very elongated but that's the term that is used for these shapes. Figure 1 shows that the 11 x 89 x 941 looks more like a plank than a brick.
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Figure 1 |
There may well be more beyond the three million mark but SageMathCell timed out above that. Anyway, fascinating that such numbers exist with the first of them being 366, the number of days in a leap year. It can be noted that 366 is the only even number. Placed in sequence on the number line we have:
366, 663, 3245, 3685, 5423, 5863, 921239, 932129
This sequence of terms could be described thus:
Non-palindromic sphenic numbers which, when reversed, are also sphenic numbers with the members of both pairs having identical sphenic brick surface areas.
Not surprisingly this sequence does not appear in the OEIS, nor will it, as I have ceased to contribute.
ADDENDUM:
The above idea can be applied to semiprimes as well. In this case we will be working with two dimensional rectangles. The two factors of the semiprime form the length and width of the associated rectangle. In the range up to one million, reversible semiprimes comprise 6.06% of the total range but there are only 26 reversible semiprimes with the property that their associated areas are equal. See permalink for calculation.
14269 = 19 x 751 --> 1540 and 96241 = 157 x 613 --> 154015167 = 29 x 523 --> 1104 and 76151 = 271 x 281 --> 110416237 = 13 x 1249 --> 2524 and 73261 = 61 x 1201 --> 252418449 = 19 x 971 --> 1980 and 94481 = 107 x 883 --> 198018977 = 7 x 2711 --> 5436 and 77981 = 29 x 2689 --> 543636679 = 43 x 853 --> 1792 and 97663 = 127 x 769 --> 1792140941 = 97 x 1453 --> 3100 and 149041 = 103 x 1447 --> 3100150251 = 347 x* 433 --> 1560 and 152051 = 383 x 397 --> 1560196891 = 401 x 491 --> 1784 and 198691 = 431 x 461 --> 1784302363 = 211 x 1433 --> 3288 and 363203 = 263 x 1381 --> 3288308459 = 173 x 1783 --> 3912 and 954803 = 937 x 1019 --> 3912319853 = 317 x 1009 --> 2652 and 358913 = 379 x 947 --> 2652958099 = 761 x 1259 --> 4040 and 990859 = 839 x 1181 --> 4040
It can be noted that all these reversible semiprimes are odd.
If we are even more adventurous we can consider numbers with four distinct factors as being associated with 4-dimensional hypercuboids. When unfolded into 3-dimensions, the eight cuboids are the equivalent of the surface area of our sphenic bricks. In the range up to three million, about 1.48% of numbers are reversible four factor numbers with the first one being 1518 = 2 x 3 x 11 x 23 and 8151 = 3 x 11 x 13 x 19. However, no number pairs emerge with identical volumes of unfolded cuboids. Figure 1 shows an unfolded hypercube and an unfolded hypercuboid will look similar but will have four pairs of cuboids each with different volumes, instead of consisting of eight identical cubes. Permalink (which may need double checking).
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Figure 1 |
Thursday, 11 July 2019
Sphenic Brick Trajectories
- Sphenic Numbers on Monday, 25th June 2018
- Sphenic Numbers Revisited on Tuesday, 1st January 2019
- An Unhappy Family on Monday, 10th June 2019
This is indeed the case for 170 because its surface area of 258 = 2 * 3 * 43 and can thus be linked to a prism with volume of 258 cubic units and dimensions of 2, 3 and 43 units. This prism has a surface area of 442 square units. The obvious question is: can this process be continued? Well 442 = 2 * 13 * 17 and so the answer is yes. The resulting prism has a surface area of 562 square units but 562 = 2 * 281 and so this is where things stopped.- [7386, 12322, 12970, 18178, 19018, 20194, 22042, 22882, 25642]
- [8078, 10414, 11086, 12142, 14062, 14734, 15502, 16942, 17902]
- [9514, 10066, 12970, 18178, 19018, 20194, 22042, 22882, 25642]
- [9515, 5646, 9422, 12142, 14062, 14734, 15502, 16942, 17902]
- [9562, 12322, 12970, 18178, 19018, 20194, 22042, 22882, 25642]
- [10634, 12322, 12970, 18178, 19018, 20194, 22042, 22882, 25642]
- [15085, 10414, 11086, 12142, 14062, 14734, 15502, 16942, 17902]
- [15110, 21174, 35302, 39094, 46246, 51190, 71686, 73942, 87430]
- [15654, 26102, 27910, 39094, 46246, 51190, 71686, 73942, 87430]
- [23313, 18110, 25374, 42302, 48862, 57790, 80926, 84862, 86590]
- [27363, 26102, 27910, 39094, 46246, 51190, 71686, 73942, 87430]
- [28217, 10414, 11086, 12142, 14062, 14734, 15502, 16942, 17902]
- [30173, 10414, 11086, 12142, 14062, 14734, 15502, 16942, 17902]
- [30441, 21566, 22782, 37982, 48862, 57790, 80926, 84862, 86590]
- [32331, 26606, 27822, 46382, 59662, 64942, 71854, 75886, 83950]
- [35121, 26606, 27822, 46382, 59662, 64942, 71854, 75886, 83950]
So starting with 7386, there is then a run of eight sphenic numbers generated by the volume-area iteration. The run ends at 25642 which is not a sphenic number. Similarly for the other chains shown and it should be noted that several chains merge into others. For example, 7386, 9514 and 9562, all end with 25642. So, how many iterations are possible? Well, up to \( \textbf{ten million}\), there are three chains of 15 iterations, all ending in \( \textbf{10186102} \) (permalink):
- 8710117, 1384374, 2307302, 2394582, 3990982, 4009942, 4044454, 4470262, 4758790, 6662326, 7873702, 8021302, 8362822, 9649462, 9733222, 10186102
The factorisations are:
number factor 8710117 13 * 613 * 1093 1384374 2 * 3 * 230729 2307302 2 * 53 * 21767 2394582 2 * 3 * 399097 3990982 2 * 467 * 4273 4009942 2 * 239 * 8389 4044454 2 * 19 * 106433 4470262 2 * 31 * 72101 4758790 2 * 5 * 475879 6662326 2 * 11 * 302833 7873702 2 * 107 * 36793 8021302 2 * 47 * 85333 8362822 2 * 13 * 321647 9649462 2 * 233 * 20707 9733222 2 * 43 * 113177
101861022 * 23 * 79 * 2803 - 9469213, 1768854, 2948102, 2958742, 3118822, 4009942, 4044454, 4470262, 4758790, 6662326, 7873702, 8021302, 8362822, 9649462, 9733222, 10186102
The factorisations are:
number factor 9469213 13 * 61 * 11941 1768854 2 * 3 * 294809 2948102 2 * 787 * 1873 2958742 2 * 37 * 39983 3118822 2 * 7 * 222773 4009942 2 * 239 * 8389 4044454 2 * 19 * 106433 4470262 2 * 31 * 72101 4758790 2 * 5 * 475879 6662326 2 * 11 * 302833 7873702 2 * 107 * 36793 8021302 2 * 47 * 85333 8362822 2 * 13 * 321647 9649462 2 * 233 * 20707 9733222 2 * 43 * 113177
101861022 * 23 * 79 * 2803 - 9749077, 1768854, 2948102, 2958742, 3118822, 4009942, 4044454, 4470262, 4758790, 6662326, 7873702, 8021302, 8362822, 9649462, 9733222, 10186102
The factorisations are:
number factor 9749077 13 * 73 * 10273 1768854 2 * 3 * 294809 2948102 2 * 787 * 1873 2958742 2 * 37 * 39983 3118822 2 * 7 * 222773 4009942 2 * 239 * 8389 4044454 2 * 19 * 106433 4470262 2 * 31 * 72101 4758790 2 * 5 * 475879 6662326 2 * 11 * 302833 7873702 2 * 107 * 36793 8021302 2 * 47 * 85333 8362822 2 * 13 * 321647 9649462 2 * 233 * 20707 9733222 2 * 43 * 113177
101861022 * 23 * 79 * 2803
Monday, 25 June 2018
Sphenic Numbers
A number \(n\) is called sphenic if it is the product of 3 distinct primes.
For example, 370 is a sphenic number because it is the product of the 3 primes 2, 5 and 37.
Sphenic numbers are quite common: up to \(10^8\) there are 20,710,806 sphenic numbers.
The sum of the reciprocals of the sphenic numbers diverges, while the sum of the reciprocal of their squares converges to 0.003696244... , which can be expressed as \((P(2)^3-3\,P(2)\,P(4)+2\,P(6))/6\), where $$P(s)=\sum_{p\mathrm{\ prime}}\frac{1}{p^s}$$is the so-called prime Zeta function
The first sphenic numbers are 30, 42, 66, 70, 78, 102, 105, 110, 114, 130, 138, 154, 165, 170, 174, 182, 186, 190, 195, 222, 230, 231, 238, 246, 255, 258, 266, 273, 282, 285, 286, 290, 310The sum of the reciprocals of the squares of the sphenic numbers does indeed approach 0.003696244 as can be seen by taking the numbers from 30 to 310 and applying the following SAGE code:
INPUT:
sphenic=[30, 42, 66, 70, 78, 102, 105, 110, 114, 130, 138, 154, 165, 170, 174, 182, 186, 190, 195, 222, 230, 231, 238, 246, 255, 258, 266, 273, 282, 285, 286, 290, 310]
sum=0
for n in sphenic:
sum+=1/n^2
print(sum.n())
OUTPUT:
0.00320320889263633
The following is a modification of the Wikipedia entry for sphenic numbers:
In number theory, a sphenic number is a natural number|positive integer that is the product of three distinct prime numbers. Thus a sphenic number is a product ''pqr'' where ''p'', ''q'', and ''r'' are three distinct prime numbers. This definition is more stringent than simply requiring the integer to have exactly three prime factors. For instance, \(60 = 2^2 × 3 × 5 \) has exactly 3 prime factors, but is not sphenic.
The smallest sphenic number is 30 = 2 × 3 × 5, the product of the smallest three primes. The largest known sphenic number is
$$(2^{77232917}− 1) \cdot (2^{74,207,281} − 1) \cdot (2^{57,885,161} − 1)$$It is the product of the three largest known primes.
All sphenic numbers have exactly eight divisors. If we express the sphenic number as \(n = p \cdot q \cdot r \), where ''p'', ''q'', and ''r'' are distinct primes, then the set of divisors of ''n'' will be { 1, p, q, r, pq, pr, qr, n }.
The converse does not hold. For example, 24 is not a sphenic number, but it has exactly eight divisors.
All sphenic numbers are by definition squarefree, because the prime factors must be distinct.
The Möbius function of any sphenic number is -1.
The first case of two consecutive sphenic integers is 230 = 2×5×23 and 231 = 3×7×11. The first case of three is 1309 = 7×11×17, 1310 = 2×5×131, and 1311 = 3×19×23. There is no case of more than three, because every fourth consecutive positive integer is divisible by 4 = 2×2 and therefore not square-free.
The numbers 2013 (3×11×61), 2014 (2×19×53), and 2015 (5×13×31) are all sphenic. The next three consecutive sphenic years will be 2665 (5×13×41), 2666 (2×31×43) and 2667 (3×7×127) (see OEIS A165936).The OEIS sequence A007304 (sphenic numbers, products of 3 distinct primes) mentions that a sphenic brick is a rectangular parallelopiped whose sides are components of a sphenic number, namely whose sides are three distinct primes. For example, the distinct prime triple (3,5,7) produces a 3 x 5 x 7 unit brick which has volume 105 cubic units.
From my early days of investigating numbers, I had considered triprimes (number that factor into three, not necessarily distinct, primes) as having unique representations as rectangular prisms. I was interested in the relationship between a prisms volume and its surface area, coining the term "cubicity". Here is a snapshot of a February 2014 Instagram post:


















