Figure 1 |
It so happens that the number representing my diurnal age today, 26149, is a member of this "very generalized Fibonacci sequence" and is in fact OEIS A050443:
A050443 | a(0)=4, a(1)=0, a(2)=0, a(3)=3; thereafter a(n) = a(n-3) + a(n-4). |
4, 0, 0, 3, 4, 0, 3, 7, 4, 3, 10, 11, 7, 13, 21, 18, 20, 34, 39, 38, 54, 73, 77, 92, 127, 150, 169, 219, 277, 319, 388, 496, 596, 707, 884, 1092, 1303, 1591, 1976, 2395, 2894, 3567, 4371, 5289, 6461, 7938, 9660, 11750, 14399, 17598, 21410, 26149
Figure 2: The above cartoon (Amend 2005) shows an unconventional sports application of the Perrin sequence (right panel). (The left two panels instead apply the Fibonacci numbers). |
\(P(n)\) is also the solution of a third-order linear homogeneous recurrence equation having characteristic equation \(x^3-x-1=0\). The solutions to this equation are given by:$$\begin{align} x& = -\frac{1}{2} \, {\left(\frac{1}{18} \, \sqrt{23} \sqrt{3} + \frac{1}{2}\right)}^{\frac{1}{3}} {\left(i \, \sqrt{3} + 1\right)} - \frac{-i \, \sqrt{3} + 1}{6 \, {\left(\frac{1}{18} \, \sqrt{23} \sqrt{3} + \frac{1}{2}\right)}^{\frac{1}{3}}}\\x &= -\frac{1}{2} \, {\left(\frac{1}{18} \, \sqrt{23} \sqrt{3} + \frac{1}{2}\right)}^{\frac{1}{3}} {\left(-i \, \sqrt{3} + 1\right)} - \frac{i \, \sqrt{3} + 1}{6 \, {\left(\frac{1}{18} \, \sqrt{23} \sqrt{3} + \frac{1}{2}\right)}^{\frac{1}{3}}}\\ x &= {\left(\frac{1}{18} \, \sqrt{23} \sqrt{3} + \frac{1}{2}\right)}^{\frac{1}{3}} + \frac{1}{3 \, {\left(\frac{1}{18} \, \sqrt{23} \sqrt{3} + \frac{1}{2}\right)}^{\frac{1}{3}}}\end{align} $$The third and only real-valued solution above is the so-called plastic constant \( \approx 1.32471795... \), also called the:
- le nombre radiant
- minimal Pisot number
- plastic number
- plastic ratio
- platin number
- Siegel's number
- silver number
- silver constant
Figure 3 |
It was only after composing this post that I realised I had already made a post about the plastic number on Friday, 5th June 2020. This is well worth the read because it illustrates some applications of the number (as shown in Figure 3). The Greek letter \( \rho \) can be used to represent the plastic ratio. In which case, to quote from the earlier post and referencing Figure 3:
There are precisely three ways of partitioning a square into three similar rectangles:
The trivial solution given by three congruent rectangles with aspect ratio 3:1.
The solution in which two of the three rectangles are congruent with the third one of twice the linear dimension of the congruent pair and where the rectangles have aspect ratio 3:2.
The solution in which the three rectangles are mutually non-congruent (all of different sizes) and where they have aspect ratio \( \rho^2 \). The ratios of the linear sizes of the three rectangles are: \( \rho \) (large : medium); \( \rho^2\)(medium : small); and \( \rho^3 \) (large : small). The internal, long edge of the largest rectangle (the square's fault line) divides two of the square's four edges into two segments each that stand to one another in the ratio ρ. The internal, coincident short edge of the medium rectangle and long edge of the small rectangle divides one of the square's other, two edges into two segments that stand to one another in the ratio \(\rho^4\).
Figure 4 shows the approximate measurements for a unit square in which the three rectangles are mutually non-congruent. We have:$$ \frac{b}{1-b}=\rho$$
Figure 4 |
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