This post builds on my two previous posts so it's best to look at those first in order to properly understand what I'm doing. These posts are:
Looking at the maximal values associated with progressively summing the squares of dyads, triads, tetrads etc. and then finding the sum of their digits, the need for a consistent notational system arose. I wanted to be able to describe that specific term in the sequence with the maximum value for a particular k. Thus I came up with akmax,N for this maximum value where k is the exponent and N is the number of terms that are being added together. Let's look at some specific examples:DYAD
akmax,N=2 can be used to represent the maximum value attained by an for a particular k when summing two terms progressively, where:an= sum of digits (akn−1+akn−2) with a0=0,a1=1The sequence for 2≤k≤50 is as follows:
[14, 28, 35, 45, 56, 91, 83, 110, 98, 135, 128, 151, 155, 181, 197, 218, 200, 241, 275, 271, 296, 286, 308, 319, 341, 351, 350, 376, 353, 410, 443, 433, 395, 495, 443, 501, 551, 521, 548, 565, 614, 620, 614, 604, 611, 646, 641, 716, 701]
So we can write a2max,N=2=14, a3max,N=2=28 etc.
TRIAD
akmax,N=3 can be used to represent the maximum value attained by an for a particular k when summing three terms progressively, where:an= sum of digits (akn−1+akn−2+akn−3) with a0=0,a1=1,a2=2The sequence for 2≤k≤50 is:
[24, 34, 35, 58, 66, 93, 98, 99, 117, 140, 147, 165, 191, 181, 197, 218, 236, 248, 266, 297, 297, 311, 309, 347, 344, 362, 360, 408, 416, 436, 425, 449, 479, 482, 479, 544, 546, 546, 566, 570, 597, 624, 632, 702, 665, 664, 696, 710, 725]
So we can write a2max,N=3=24, a3max,N=3=34 etc.
TETRAD
akmax,N=4 can be used to represent the maximum value attained by an for a particular k when summing four terms progressively, where:an= sum of digits (akn−1+akn−2+akn−3+akn−4) with a0=0,a1=1,a2=2,a3=3The sequence for 2≤k≤50 is:
[26, 28, 47, 56, 57, 82, 99, 118, 119, 147, 173, 183, 188, 206, 209, 214, 236, 282, 263, 271, 297, 311, 335, 338, 371, 357, 389, 409, 399, 442, 459, 476, 485, 457, 525, 541, 575, 567, 566, 633, 579, 651, 659, 666, 666, 699, 722, 762, 764]
So we can write a2max,N=4=26, a3max,N=4=28 etc.
PENTAD
akmax,N=5 can be used to represent the maximum value attained by an for a particular k when summing five terms progressively, where:an= sum of digits (akn−1+akn−2+akn−3+akn−4+akn−5) with a0=0,a1=1,a2=2,a3=3,a4=4The sequence for 2≤k≤50 is:
[26, 37, 38, 63, 65, 98, 92, 118, 122, 147, 156, 186, 197, 199, 198, 234, 255, 266, 281, 306, 324, 324, 335, 362, 357, 380, 405, 408, 426, 458, 474, 496, 504, 510, 516, 559, 557, 577, 563, 604, 588, 628, 657, 667, 695, 709, 686, 754, 764]
So we can write a2max,N=5=26, a3max,N=5=37 etc.
HEXAD
akmax,N=6 can be used to represent the maximum value attained by an for a particular k when summing six terms progressively, where:an= sum of digits (akn−1+akn−2+akn−3+akn−4+akn−5+akn−6) with a0=0,a1=1,a2=2,a3=3,a4=4,a5=4The sequence for 2≤k≤50 is:
[26, 39, 47, 66, 78, 91, 98, 118, 131, 147, 167, 175, 191, 207, 234, 232, 230, 269, 281, 288, 311, 335, 329, 355, 380, 393, 452, 412, 437, 440, 464, 486, 509, 510, 528, 544, 585, 575, 576, 608, 617, 630, 654, 656, 684, 705, 725, 734, 764]
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