In terms of the numbers associated with my diurnal age, I recently concluded a run of six numbers (a sextuplet) with the shared property that they could all be written as a product of three, not necessarily distinct, prime factors. These were the numbers together with their factorisations:
- 27290 = 2 * 5 * 2729
- 27291 = 3 * 11 * 827
- 27292 = 2^2 * 6823
- 27293 = 7^2 * 557
- 27294 = 2 * 3 * 4549
- 27295 = 5 * 53 * 103
A045942 | Numbers \(m\) such that the factorisations of \(m \dots m+5\) have the same number of primes (including multiplicities). |
Such numbers are few and far between. The initial members of the sequence are:
2522, 4921, 18241, 25553, 27290, 40313, 90834, 95513, 98282, 98705, 117002, 120962, 136073, 136865, 148682, 153794, 181441, 181554, 185825, 204323, 211673, 211674, 212401, 215034, 216361, 231002, 231665, 234641, 236041, 236634, 266282, 281402, 284344, 285410
A123103 | Numbers \(m\) such that the factorisations of \(m \dots m+6\) have the same number of primes (including multiplicities). |
The initial members are:
211673, 298433, 355923, 381353, 460801, 506521, 540292, 568729, 690593, 705953, 737633, 741305, 921529, 1056529, 1088521, 1105553, 1141985, 1187121, 1362313, 1721522, 1811704, 1828070, 2016721, 2270633, 2369809, 2535721, 2590985
Let's look at the septuplet beginning with 211673:
- 211673 = 7 * 11 * 2749
- 211674 = 2 * 3 * 35279
- 211675 = 5^2 * 8467
- 211676 = 2^2 * 52919
- 211677 = 3 * 37 * 1907
- 211678 = 2 * 109 * 971
- 211679 = 13 * 19 * 857
There are longer runs but the numbers then become very large: A358017 (\(k=8\)), A358018 (\(k=9\)), A358019 (\(k=10\)).
ADDENDUM: March 6th 2024
Today I created a post that more or less reproduced what I've covered here. I had to delete it because it was largely redundant. Now that I have so many posts it's important that I check first before I create posts. The hashtags become very important in this context.
No comments:
Post a Comment